Biological systems require energy to do work, to make complicated molecular assemblies out of simple building blocks, to regulate temperature, etc.
Basic Thermodynamics Concepts
First, you need to distinguish between the "system" (the object being studied) and "surroundings" (everything else in the universe). The system is often a cell, but may also be a biological polymer or molecule (the basic thermodynamic laws apply whether the system is "living" or not).
There are three types of thermodynamic systems:
The First Law of Thermodynamics
"Conservation of Energy"
Forms of energy
Changes in the energy of a system
DE = E2 - E1
How might such energy be transferred between system and surroundings?
DE = E2 - E1 = q + w
w = Force * distance = F * d
The manifestation of "work" in biological systems is often concerned with pressure and volume changes
DV = V2 - V1
(where V2 is final volume, V1 is initial volume)
w = -P * DV
thus
DE = q + (-P * DV)
The change in the internal energy of the system is related to the heat energy transferred to (or from) the system plus any pressure-volume work performed on system (or on surroundings by the system)
Enthalpy
DE = q + w. Therefore, if no work is performed during some change in state of a biological system, then the energy transfer is entirely in the form of heat energy (i.e. energy transferred by radiation rather than direct mechanical coupling)
Tragically, most biological systems have evolved under conditions of constant pressure (i.e. we are under 1 atm pressure, and this is pretty much constant for most "systems" in our body during their thermodynamic changes). Thus, it is not feasible to be able to study and measure biological systems under conditions of constant volume (where we would know that the change in energy is entirely quantitated by the heat transferred between system and surroundings)
Another thermodynamic term, ENTHALPY (H), has been defined as the following:
H = E + (P * V)
Enthalpy = Internal energy plus pressure-volume contributions to energy
DH = DE + (P * DV)
DH = {q - (P * DV)} + (P * DV)
DH = q
This means that under conditions where pressure is held constant (as with many biological systems) DH is a thermodynamic term that quantitates the heat energy (q) transferred from surroundings to the system.
What about possible volume changes and the work associated with that?
Standard State Conditions
The van't Hoff enthalpy
If we define conditions where the heat transferred is a measure of the internal energy, then the equilibrium between two thermodynamic states will be changed in response to heat transferred from the surroundings. In other words, the equilibrium will change with the temperature.
Consider an ENDOTHERMIC reaction:
A + heat energy (q) ó B
Keq = [B] / [A]
What is the relationship between Keq and temperature?
The extent to which Keq shifts in response to increases in temperature is a measure of the enthalpy change (DH) of the system
DH0 = -R * d(lnKeq)/d(1/T)
DH0 = -R * d(ln Keq) / d(1/T)
The temperature-dependent denaturation of a biological polymer can be analyzed in this way
Therefore, a positive DH0 value indicates the folded state of the protein is a lower internal energy state than the unfolded state
The internal energy difference (i.e. DH0) for protein denaturation varies somewhat with temperature, but is usually always positive (i.e. favors the folded state). However, the enthalpy is not the only contribution to the energetics of protein folding, and proteins do unfold at extremes of temperature.
The Second Law of Thermodynamics
The second law of thermodynamics deals with Entropy (or disorder) and there are several points about entropy that the second law of thermodynamics makes:
Here is an example of an irreversible process:
Step 1: I have a flask with two chambers and separated by a valve. One chamber has a gas, the other is evacuated.
Step 2: I open the valve and observe that the gas distributes between both sides.
Step 3: I reverse the process by closing the valve. Does the gas distribute back to the original side as I close the valve? No. The process is irreversible, and furthermore, the entropy has increased (the movement of gas to distribute in the container is entropy driven)
Original temp, pressure, but entropy not same as initial value (it is higher)
How is entropy quantitated?
S = k * ln(W)
Where k is the Boltzmann constant = 1.38 x 10-23 J/K
dSrev = dq/T = dH/T
What does this mean?
Heat capacity and entropy
Cp = dH / dT
The heat capacity at constant pressure = heat energy transferred / change in temperature
Quantitation of entropy in terms of heat capacity
Rearranging to give enthalpy change in terms of heat capacity and temperature change:
dH = Cp * dT
Substituting into the definition of entropy change in relationship to enthalpy change:
dS = dH/T = (Cp * dT)/T
dS = Cp * (1/T) dT
The equation can be rearranged to describe the heat capacity in terms of the entropy:
T * dS/dT = Cp
The Third Law of Thermodynamics
At 0K (i.e. absolute 0) a crystalline solid is perfectly ordered, and there is only one possible conformation (W = 1)
S = k * ln(1) = 0
Entropy is exactly 0 at 0K
Gibbs Free Energy Change
If a system gives up heat energy to the surroundings, then the new state of the system is lower in energy. Conversely, if the system absorbed energy from the surroundings, then the new state was higher in energy.
G = H - T*S
And
DG = G2 - G1 = (H2 - H1) - T * (S2 - S1)
Or
DG = DH - T*DS
(Remember, if P = constant, DH = q)
Processes that are unfavorable with regard to DH (i.e. endothermic, or absorb heat) can be driven by associated entropic changes that are favorable (i.e. increasing disorder). These are known as "entropy -driven" reactions
Conversely, processes that are favorable enthalpically, but unfavorable entropically, may be spontaneous if the enthalpic term is large enough. These are known as "enthalpy-driven" reactions
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